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A Summary of Factoring Polynomials
Factoring The Difference of 2 Squares
Factoring Trinomials
Quadratic Expressions
Factoring Trinomials
The 7 Forms of Factoring
Factoring Trinomials
Finding The Greatest Common Factor (GCF)
Factoring Trinomials
Quadratic Expressions
Factoring simple expressions
Polynomials
Factoring Polynomials
Fractoring Polynomials
Other Math Resources
Factoring Polynomials
Polynomials
Finding the Greatest Common Factor (GCF)
Factoring Trinomials
Finding the Least Common Multiples
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After studying this lesson, you will be able to:

  • Factor trinomials.

Steps of Factoring:

1. Factor out the GCF

2. Look at the number of terms:

  • 2 Terms: Look for the Difference of 2 Squares
  • 3 Terms: Factor the Trinomial
  • 4 Terms: Factor by Grouping

3. Factor Completely

4. Check by Multiplying

This lesson will concentrate on the second step of factoring:Factoring Trinomials.

**When there are 3 terms, we are factoring trinomials. Don'tforget to look for a GCF first.**

Factoring trinomials often requires some trial and error.Don't get frustrated. Try all possible combinations. In theprevious problems, the first term has not had a coefficient. Wewill now look at problems that do have coefficients in the firstterm. This adds another level of trial and error or"guessing".

One thing that will make the "guessing" moreaccurate is to look for a prime number in the first term or theconstant term. Remember, a prime number only has 2 factors.....1and itself. If the coefficient of the first term or the constantterm is prime, start there and "lock in" those factors.

 

Example 1

Factor 5x 2 - 17x + 14

This is a trinomial (has 3 terms). There is no GCF other thanone. So, we start with 2 parentheses:

Using our signs rules, we can determine the signs for thefactors. Since the constant term is positive we know the signswill be the same. Since we want the factors to add up to -17x thesigns will both have to be negative. Keep this in mind.

1 st : Since the coefficient of the first term is prime (5),we will start with the first term. Find the factors of the firstterm. The factors of 5x 2 are 1x and 5x. These go inthe first positions. We can also go ahead and put in the signs(both negative)

2 nd : Find the factors of the constant term. The factors of14 are 1,14 and 2, 7. Remember, we need the inside/outsidecombination to add up to the middle term which is -17x. This timewe don't just consider the factors of the constant term becausethe first term also had factors. Here's where the guessing comesin. Let's try the factors 2,7 and see what happens.

(1x - 2 ) (5 x - 7 ) Let's check the inside/outsidecombination. If we multiply inside, -2 times 5x gives us -10x.Multiplying outside 1x times -7 gives us -7x. Add up theinside/outside combination: -10x + -7x is equal to -17x which isour middle term. We made a lucky guess!! Note: If the 2 and 7hadn't worked, we should try 7 and 2. If that didn't work either,we would try 1 and 14 or 14 and 1. The point is, you keep tryinguntil you find the right combination.

Check by using FOIL (x - 2) (5x - 7) 5x 2 - 7x - 10x + 14 which is5x 2 - 17x + 14

 

Example 2

Factor 8x 2 - 10x + 3

This is a trinomial (has 3 terms). There is no GCF other thanone. So, we start with 2 parentheses:

Using our signs rules, we can determine the signs for thefactors. Since the constant term is positive we know the signswill be the same. Since we want the factors to add up to -10x thesigns will both have to be negative. Keep this in mind.

1 st : Since the coefficient of the constant term is prime(3), we will start with the constant term. Find the factors ofthe first term. The factors of 3 are 1 and 3. These go in thelast positions. We can also go ahead and put in the signs (bothnegative)

2 nd : Find the factors of the first term. The factors of 8x2 are 1x, 8x and 2x, 4x. Remember, we need theinside/outside combination to add up to the middle term which is-10x. This time we don't just consider the factors of theconstant term because the first term also had factors. Here'swhere the guessing comes in. Let's try the factors 4x ,2x and seewhat happens.

(4x - 1 ) (2x - 3 ) Let's check the inside/outsidecombination. If we multiply inside, -1 times 2x gives us -2x.Multiplying outside 4x times -3 gives us -12x. Add up theinside/outside combination: -2x + -12x is equal to -14x which isNOT our middle term. This is not a lucky guess. Ok, let's reversethe factors 4x, 2x and try it that way:

(2x - 1 ) ( 4x - 3) Let's check the inside/outsidecombination. If we multiply inside, -1 times 4x gives us -4x.Multiplying outside 2x times -3 gives us -6x. Add up theinside/outside combination: -4x + -6x is equal to -10x which isour middle term.

Check by using FOIL (2x - 1) (4x - 3) 8x 2 - 6x - 4x + 3 which is 8x2 - 10x + 3